Переведите одну девятую 1/9 и две девятых 2/9 в проценты !

1/9*100%=11.11% и 2/9*100%=22.22%              

1)   -2x^2 + 3x + 5 = 0

d = 9+40 = 49

x1 = (-3+7)/(-4) = -1

x1 = (-3-7)/(-4) = 2,5

 

-2x^2 - x +1 = 0

d = 1 + 8 = 9

x1= (1+3) / (-4) = -1

x1 = (1-3) / (-4) = 0,25

 

(5 + 3x - 2x^2) / ( 1-x-2x^2) = ((x+1)(x-2,5)) / ((x+1)(x-0,25)) = (x-2,5) / (x-0.25_

 

  2) 3x^2-4x-4 = 0

d = 16 + 48 = 64

x1=(4+8)/6 = 2

x2=(4-8)/6=-2/3

 

-x^2-x+6=0

d=1+24=25

x1=(1-5)/(-2)=2

x2=(1+)=-3

 

 

(3x^2-4x-4)/(6-x-x^2) = ((x+2/3)(x-2)) / ((x-2)(x+3)) = (x+2/3) / (x+3)

 

 

 

   

1) 2√a + 6√a - 7√a = (2 + 6 - 7)√a = 1 * √a = √a 2) 2√a + 3√b + 3√a = (2 + 3)√a + 3√b = 5√a + 3√b 3) √(9a) + √(25a) - √(36a) = 3√a + 5√a - 6√a = (3 + 5 - 6)√a = 2√a 4) √32 + √18 - √50 = √(16*2)+√(9*2) -√(25*2) = 4√2 + 3√2 - 5√2 = 2√2 5) 3√(12b) + 0.5√(108k) - 2√(48b) + 0.01√(300k) =       = 3√(4*3b) + 0,5√(36*3k) - 2√(16*3b) + 0,01√(100*3k) =       = 6√(3b) + 3√(3k) - 8√(3b) + 0,1√(3k) = 3,1√(3k) - 2√(3b) 1. (√3 + √x)(√3 - √x) = (√3)² - (√x)² = 3 - x 2. (√x + √3)² = (√x)² + 2√x *√3 + (√3)² = x + 3 + 2√(3x) 3. (2√3 - 3√2)² = 4*3 - 12√6 + 9*2 = 30 - 12√6 4. (5√3 - √11)(5√3 + √11) = (5√3)² - (√11)² = 25*3 - 11 = 64 5. (√(2a) + b)(2a - b√(2a) + b²) = (√(2a))³ + b³