vadim1140
?>

Log8 ( x+7) = log 8 (2x -15) объясните подробно !

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Ответы

osuvorova7979

log8(x+7)=log8(2x-15)

 

1. область допустимых значений:

 

{x+7> 0;     {x> -7;

{2x-15> 0; {x> 7.5;

 

2. раз основания логарифма одинаковые (8), сразу же их потенцируем:

 

log8(x+7)=log8(2x-15)

x+7=2x-15

2x-x=15+7

x=22

 

 

websorokin

2 представляем как log49 по основанию 7log(8-x) по основанию 7= log49 по основанию 7получаем 8-x=49 x=8-49 x=-41ответ: -41

vera-classic75

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Must Waste More Time...

Федор_Рауф1592

Объяснение:

1) Квадратичная функция имеет вид ах² + bx + c, поэтому подходит ответ под буквой а) y = 3x - x²

2) Нулями функции называются такие значения х, при которых значение функции (т. е. y) равно нулю

а) у = х² - 6х + 8 = 0

Решим квадратное уравнение через дискриминант.

x = 2

x = 4

Это и есть нули функции

б) y = 2x² + 6x

Вынесем общий множитель 2х

2х(х + 6) = 0

Произведение равно нулю, когда хотя бы один из множителей равен нулю.

2х = 0

х + 6 = 0

х = 0

х = -6

в) у = -2х² + 3х + 5 = 0

Домножим на -1, чтобы избавиться от минуса перед иксом

2х² - 3х - 5 = 0

Решаем через дискриминант:

x = 1

x =  5/2

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Log8 ( x+7) = log 8 (2x -15) объясните подробно !
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