Заполните пропуски правильной формой глагола have to, should, ought to. и переведите предложения. 1. the bus was late so we wait for half and hour. 2. the doctor says that you give up smoking as soon as possible. 3. the car was out of order so we take a taxi. 4. he tell a lie to save the situation. 5. you think twice about it. 6. i`m afraid you take the exam again. 7. you use such rude words! 8. she be more friendly. 9. he have two jobs to keep his family. 10. you consult your doctor about it. 11. you be more careful with you money. 12. you write two tests next week. 13. my brother work hard before he entered the university.

1had to
2should
3had to
4has to
5should
6you'll have to
7shouldn't
8ought to
9has to
10should
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12you 'll have to
13had to

I’ll never forget …having sailed (sail) down the Volga on that lovely summer day.

I am so sorry; I forgot …letting (let) you know.

Don’t forget …to remind (remind) them about the party.  

I remember …having seen (see) you somewhere.  

Did you remember …to water.. (water) the plants today?  

I’m sorry …………to…interruping……….. (interrupt), but can I ask you something?

Bob was sorry for …………has……shout…….. (shout) at his little sister.

He stopped ……………to smoke……….. (smoke) when he realised how dangerous it was.

Amanda stopped ………………his …….. (have) a quick snack and then continued translating the article.

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You should try ……………exercising……….. (exercise), you may feel better.

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#include <stdio.h>

#include <stdlib.h>     // предоставляет rand() и srand()

#include <time.h>       // предоставляет time()

 

// число строк в массиве:

#define M 5

// длина каждой строки:

#define N 7

 

int main ()

{

   srand(time(NULL));      // новая точка отсчета рнд

   int B[M][N];            // массив

   int cnt;                // число отрицательных

   int i, j;

 

   // заполняем массив случайными:

   for (i=0; i<M; i++)

       for (j=0; j<N; j++)

           B[i][j] = rand() %21 - 10;

 

   // считаем отрицательные:

   for (i=0; i<N; i++)

   {

       cnt = 0;        // перед каждым новым столбцом сбрасываем счетчик отрицательных

       for (j=0; j<M; j++)

           if (B[i][j] < 0) cnt++;

       printf("column #%i, count is: %d\n", i, cnt);

   }

 

   return 0;   // конец программы