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Написать росказ на про спорт и здоровье.

Английский язык

Ответы

Surkova_Pavlovna
I very much love sport! Our family leads a healthy lifestyle. Every weekend we try to carry out everything together in the fresh air actively playing sports. In the summer we swim, we play soccer, volleyball and badminton. We play snowballs in the winter and we ski. Also we become tempered. It strengthens health and helps not to hurt. The sport is health!
sky-elena712558

а) предложения, в которых ing-форма является подлежащим

The driving wheel of the machine is broken.

These happenings are remarkable.

Travelling is a pleasant way of improving one’s education.

Asking him for help is useless.

в) предложения, в которых ing-форма является обстоятельством

Every trust arranges for the marketing of its products.

It is no use crying over spilt milk.

We have every chance of passing our examinations well.

You don’t know what you miss, not having the desire to listen to good music.

с) предложения, в которых ing-форма является частью сказуемого.

Happily we escaped being delayed on our way.

Having been knocked down by a passing car, the poor man was at once taken to hospital.

I was told of a great friendship existing between two captains.

Driving in a motor car, we passed many villages.

Объяснение:

krasilnikov74
Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5

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