Fill in the graps with suitable articles english language of diplomacy , sports and music. 2. fredi is from germany . he's german and speats __ german. 3. hereko's from japan .hisd native language is japanese. 4. jaime and diego are from spain. they are spanish. they apeak spanish and english. 5.jen claude is from france. jean's french. he french 6. mahammad is from morocco. he can arabic, english, and french. japanese have long and interesting history ( если где ненужны артикли то пишите - )

1 English is the language of diplomacy, sports and music.
2. Fredi is from Germany . He's German and speaks German.
3. Hereko's from Japan .His native language is Japanese.
4. Jaime and Diego are from Spain. They are Spanish. They speak Spanish and English.
5.Jen Claude is from France. Jean's French. He speaks French.
6. Mahammad is from Morocco. He can speak Arabic, English, and French.
7 The Japanese have a long and interesting history.

а) предложения, в которых ing-форма является подлежащим

The driving wheel of the machine is broken.

These happenings are remarkable.

Travelling is a pleasant way of improving one’s education.

Asking him for help is useless.

в) предложения, в которых ing-форма является обстоятельством

Every trust arranges for the marketing of its products.

It is no use crying over spilt milk.

We have every chance of passing our examinations well.

You don’t know what you miss, not having the desire to listen to good music.

с) предложения, в которых ing-форма является частью сказуемого.

Happily we escaped being delayed on our way.

Having been knocked down by a passing car, the poor man was at once taken to hospital.

I was told of a great friendship existing between two captains.

Driving in a motor car, we passed many villages.

Объяснение:

Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5