My attitude to drugs is very negative. drugs, it is very,very bad thing! it in no case can not be used! people who accept them(almost all) are doomed to death. approximately 45% of their use, but to live there remain only 15%. for the use of the "hemp" put in jail.
akinin95
12.03.2020
1. there are a lot of beautiful buildings in moscow. 2. the kremlin is in the center of moscow. 3. exercise 6 is on the next page.4. there is a picture for the oral presentation on the 20th page. 5. there were some mistakes in his report. 6. there is nothing interesting in this article.7. the original of levitan's painting "at the pool" is in the tretyakov gallery. 8. there are a lot of full water rivers in siberia.9. how many theaters are there on sverdlov square? - there are three theaters on sverdlov square. 10. where is the bolshoi theatre? - it is on sverdlov square.11.there are many historical monuments in leningrad.12. there were no schools in many russian's villages before the october revolution.
SEMENOV25352
12.03.2020
Special sign - fluffy striped tail. the feet are large and flat with a prehensile fingers, coat thick brownish-grey. the muzzle is short with large erect ears, around the eyes, dark spots in the form of a mask on a light muzzle. compared with other predators hearing and vision raccoons developed medium, and smell good. they willingly climb and, despite its weight, very cleverly vkarabkivatsya on the tops of the trees. distinctive feature is the ingenuity and adaptability to the environment. the raccoon polosko acclimatized in germany, belarus, azerbaijan, the far east and in several other places.raccoons climb trees well, and live predominantly in the holes (or holes).
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Напишитесочинение на на тему my opinion to drugs по плану : вступление осн. your attitude
ответ:
6) соединение параллельное
=> u1=u2=u
t=1 мин = 60 с
ответ: a=50 дж
7) q=m(угля)q
q= 3,4*10^7 - древесный уголь (дж/кг)
нагревание льда
q1=cm(льда)t
с=2100 дж/(кг*°с)
t=0-(-10)=10°c
расплавка лёд
q2=(лямда)m(льда)
лямда=3,3*10^5 дж/кг
нагреть до т.кипения:
q3=c(воды)*m(льда)*100
c=4200 дж/(кг*°c)
парообразование:
q4=m(льда)*l
l=2,3*10^6 дж/кг
q=q1+q2+q3+q4
m(угля)=
=> m(угля)=+c_{voda}*m_{lda}*100+m_{lda}*l}{q})
m(угля)=0,23 кг - при каменном угле
если уголь древесный:
m(угля)=0,18 кг
объяснение: