Определить эквивалентное сопротивление цепи, на рис. и токи в каждом сопротивлении, если r1=r2=r3=r4=r5=r6=8 ом, r0=0, e=96 в

R12, R34 =2*8=16 Ом, последовательно одинаковые

R1234=16/2=8 Ом -параллельно одинаковые,

R12345=8/2=4 Ом -параллельно одинаковые,

Rобщ=R12345+R6= 12 Ом

Iобщ=U/Rобщ=96/12=8А ==I6

Uab=E-I6*R6=32 B, тогда:

I1=I2=Uab/R12= 2/16=2 A, I3=I4=2A,

I5 =32/8=4A

1) english and french are spoken by them at this hotel.2) the window was broken by the little boy last week. 3) this enquiry was typed by our secretary. 4) computer is used by jill quite often. 5) some colleages were defendedby the secretary. 6) this picture was painted by picasso. 7) ten books were published by them last year. 8) this canrdigan was knitted by molly. 9) marc will be visited by george in london next year. 10) the window was opened by jim. 11) many windows were broken by frank. 12) many book are bought by lucy. 13) some letters were written by david.97

Вещества:
X -S, Y - H2SO4, Q - SO2 и Z - H2S

Количественное определение серной кислоты:
 n(NaOH)=cV= 0,1 моль
H++OH-→ H2O
n(H+)= n(OH-)= 0,1 моль
Если кислота одноосновная: n(к-ты)= n(H+) = 0,1 моль, тогда 4,9/M=0,1
 M=49 г/моль - не существует
Если кислота двухосновная: n(к-ты) = 1/2n(H+) =0,05 моль, тогда 4,9/M=0,05
M=98 г/моль - это Н2SO4

Реакции:
S + 6HNO3(к) = Н2SO4+6NO2↑+2H2O
Cu + 2H2SO4 (к) = СuSO4 + SO2↑ + 2H2O
 H2SO4 (к) + 8HI =4I2↓ +H2S↑ + 4H2O
S + O2 =SO2↑
2H2S + 3O2 =2 SO2 ↑+ 2H2O
2H2S + SO2 = 3S↓ +2H2O