LС- фильтр подключен к 1ф2т схеме. Определить q фильтра, если L=0, 8 Гн, а С=42 мкФ. Зарисовать схему.

A friend 's birthday . New Year is approaching . Getting a passport , new home - all the happy events are countless. I have before me the question - what to give friends and family ? Gift - a manifestation of good feelings : friendship, love, deep respect , he must testify that the person making the choice to think about the taste and desires of the person to whom it is intended. In the present, as in a mirror , reflects the level of culture who gives - his generosity or stinginess , intelligence and humor , frivolity and lack of taste . Not accepted without gifts , even small, inexpensive , go for a visit to a family where there are small children . Cleverly chosen gift can have a big influence on the interests of the teenager. Set of paints and crayons can awaken interest in painting . The book on archeology , life scientists, artists can help in choosing a career . For a girl with whom you are meeting for the lady of the house, where you are invited to visit, a bouquet of flowers is always appropriate . Friend with whom you have not seen , will be pleasantly surprised when you present to him any original souvenir . It is not necessary that the gift was expensive or practical thing. Very practical approach to the evaluation of the presented does not decorate the person. One day a girl gave handmade , unique shape vase , and she took it as a cheap pot , as the vase was not crystal . And the other - a bouquet of wild flowers , gathered for her , covered in dew in the morning aroma of meadows, and she is happy

3(3x-1)>2(5x-7)         5(x+4)<2(4x-5)       2(x-7)-5x<_3x-119x-3>10x-14              5x+20<8x-10           2x-14-5x-3x+11<_09x-10x-3+14>0           5x-8x+20+10<0       -6x-3<_0-x+11>0                     -3x+30<0                -6x<_3-x>-11                       -3x<-30                  x>_-0.5x<11                          x>10(-бесконечность;11)   (10;+бескон)         [-0.5;+beskon) 2x+4(2x-3)>_12x-11       x-4(x-3)<3-6x2x+8x-12-12x+11>_0      x-4x+12-3+6x<0-2x-1>_0                       3x+9<0-2x>_1                          3x<-9x<_-0.5                         x<-3(-beskon;-0.5)              (-beskon;-3)