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Какой объём воды можно поднять из артезианской скважины глубиной 50 м в течение 2 ч, если мощность электродвигателя насоса равна 2, 8 квт, а кпд установки равен 70%?

Физика

Ответы

polina0075880
Кпд = 70%(0.7)мощность электродвигателя насоса равна no=2,8  квтполезная мощность n=no*кпд=2,8  квт *70% =1,96 квт =1960 вт время t =2 ч = 2*3600 =7200 с полезная работа a=n*t=1960*7200 =14112000 дж работа равна потенциальной энергии a=еп=mgh =v*p*g*h плотность воды  p =1000 кг/м3 g =10 м/с2 объем v = a / (p*g*h)  = n*t / (p*g*h) =no*кпд*t /(p*g*h) v = 2800*0.7*7200 /(1000*10*50) = 28.224 м3
zaseche99

As a child you would wait

And watch from far away

But you always knew that you'd be the one

That work while they all play

In youth you'd lay

Awake at night and scheme

Of all the things that you would change

But it was just a dream!

Here we are, don't turn away now,

We are the warriors that built this town

Here we are, don't turn away now

We are the warriors that built this town

From dust.

Will come

When you'll have to rise

Above the best and prove yourself

Your spirit never dies!

Farewell, I've gone to take my throne above

But don't weep for me

'Cause this will be

The labor of my love

Here we are, don't turn away now

We are the warriors that built this town

Here we are, don't turn away now,

We are the warriors that built this town

From dust.

Here we are, don't turn away now

We are the warriors that built this town

Here we are, don't turn away now

We are the warriors that built this town

From dust

rs90603607904

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Какой объём воды можно поднять из артезианской скважины глубиной 50 м в течение 2 ч, если мощность электродвигателя насоса равна 2, 8 квт, а кпд установки равен 70%?
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