Решить! волна с частотой колебаний 165гц распространяется со скоростью 330 м/с. какова длина волны (м)?

Длина волны=скорость/частота=330/165=2м

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Дано:                                                 решение: vтела=0,04м³                                 f=pж*g*vт pводы=1000кг/м³                             f=1000*10*0,04=400н   найти:                                             ответ: f=400н fа-? f(архимеда) p.воды-плотность воды. p.ж - плотность жидкости (в данной : воды) g - постоянная,примерно 9,8(≈10м/с²)