Найти количество малекул содержащих в 1 грамме углекислого газа co2

1, 369 * 10 ^ 22 молекул 

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4.

(Б) - N/t

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5.

Дано:

t= 40 с

N= 240

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T− ?

Розв’язання

T = t/N

T = 40c/240 = 1/6 c

Відповідь: T = 1/6 c

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6.

Дано:

T= 2 с

_____

ν− ?

Розв’язання

v = 1/T

v = 1/2c = 0.5 Гц

Відповідь: ν = 0,5 Гц.

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7.

Дано:

R= 30 см = 0,3 м

T= 60 с

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v -?

Розв’язання

v = 2nR/T [v] = m/c

v = 2×3,14×0,3 / 60 = 0,0314 (m/c)

Відповідь: = 0,0314 m/c

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8.

Дано:

T= 8 год

= 28800 с

v= 1200 m/c

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R -?

Розв’язання

v = 2nR/T => R = vT/2n

[R] =

R = 1200 × 28800 / 2 × 3,14 ≈ 5503185 (m)

Відповідь: = 5503,2 км.

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