Найдите общее сопротивление цепи, изображенной на рис. 1. сопротивление каждого r = 5 ом. чему равна сила тока в 5, если напряжение между клеммами а и в равно 12 в?

I5 = 0,8 A

Объяснение:

R12 = R1+R2 = 5+5 = 10 Ом

R34 = R3+R4 = 5+5 = 10 Ом

R1234 = (R12*R34 ) / (R12+R34 ) =  (10*10 ) / (10+10 ) = 5 Ом

Rобщ = R1234 +R5 = 5 +10 = 15 Ом

I = U / Rобщ = 12 / 15 = 4/5 = 0,8 A

I5 = I = 0,8 A

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Объяснение:

Записываем уравнение движения тела
x= x0 + v0t - gt^2/2
x0 - начальная координата = 25м
v0 - начальная скорость = 20 м/с
g (или Аx)  - ускорение свободного падения = 10 м/с2 ( а знак минус берется от того что ускорение направлено в противоположную сторону скорости)
x= 25 + 20t -10t^2/2 = 25 + 20t -5t^2
а теперь просто подставляем все "t"шки
x1 = 25 + 20 * 2 - 5*4 = 25 + 40 - 20 = 45
х2= 25 + 20*4 - 5 * 16 = 25
x3 = 25 + 20*5 - 5*25= 0т.к тело подбросили вертикально вверх, и оно начало пападать с ускорением -10 м\с квадратную, то мы берем формулу равнозамедленного движения