Какова сила трения возникающая на тело массой 3кг, если его коэффициент трения между телом и горизонтальной поверхностью 0, 2? (g=10h/кг)

Дано: m=3 кг; μ=0,2; Fтр - ?

Из-за притяжения Земли тело давит на опору, она деформируется и действует на тело с силой N - реакцией опоры. При горизонтальном прямолинейном движении N=mg.

Fтр=μ*N=μ*mg=0,2*3*10=6 H - это ответ.

Дано:

m = 3кг

k = 0.2

g = 10м/с²

Найти:  

F

F = k*N = k*m*g

F = 0.2*3*10 = 6H

ответ: F = 6H

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