Решение 1 узнаем по таблице удельную плотность бетона ro1 = 2.2 т/м³ и воды ro2 = 1 т/м³ масса куба m1= ro1*v = 2,2*0.5 = 1,1 т. масса воды такого же объема м2 = ro2*v = 1*0,5 = 0,5 т (500 кг) а) сила для удержания в воздухе f1 = m1*g = 1.1*9,81 = 10,800 кн (килоньютон) б) в воде действует выталкивающая сила равная весу воды f2 = (м1-м2)*g = (1,1 - 0,5)*9,81 ~5,9 кн 2 дано объем бетона 4 м³. в воде. решение f3 = v*(ro1 - ro2)*g = 4*(2,2-1,0)*9,81 = 4*1.2*9.81 ~ 47.1 кн цепь выдерживает 70 кн ответ: цепь выдержит дополнительно: на воздухе - 86,3 кн - цепь не выдержит.
Новицкий1107
11.04.2023
Once, while i was walking in a park in london, i saw an old strange-looking man. he was sitting on a bench holding a closed book in his hands. i satdown on the bench and looked at the book. i saw that the book was of great interest. it was a very old copy of early byron's works. i looked at the old man in surprise and undersood that he knew i had sat on the bench because of him and the book he was holding in his hands. i smiled. "it is the last i have," he said and stretched it out to me. i took with the words, "i am a lover of old books."
4/ 2 альфа + 9/ 4 be = 1/0 n+ 12/ 6 c ( углерод)