Паскаль написать программу для вычисления всех сторон прямоугольного треугольника с катетом лежащим в против угла 30 градусов

1) #include < stdio.h> #include < stdlib.h> int sover (int n) {     int sum = 0;     for (int i = 1; i< =n/2; i++)       if (n%i==0) sum+=i;     if (sum==n)       return 1;     else return 0; } int main() {     int n;     printf ("n = ");     scanf ("%d",& n);     if (sover(n)==1)       printf ("sovershennoe");     else printf ("ne sovershennoe");     printf("\n");     system ("pause");     return 0; }2)#include < stdio.h> #include < stdlib.h> int main(){  for (int i = 1; i< =5; i++)  {    for (int j = 1; j< =5-i+1; j++)      printf ("%d ",5+i-1);     printf ("\n");   }  system ("pause");   return 0; }

1) a := 4;  

b := 6;

b := 8 + a * b;

a := b / 4 * a.

а = 4

b = 6

b = 8 + 4 * 6 = 32

a = 32 / 4 * 4 = 32 / 16 = 2

2) a := 3;

b := 6;

b := 12 + a * b;

a := b / 5 * a.

a = 3

b = 6

b = 12 + 3 * 8 = 30

a = 30 / 5 * 3 =  6 * 3 = 18

3) a := 8;

b := 8 + a / 2;

a := a – b / 2.

a = 8

b = 8 + 8 / 2 = 12

a = 8 - 12 / 2 = 8 - 6 = 2

4) a := 2;

b := 6;

b := 12 + a * b;

a := b / 4 * a.

a = 2

b = 6

b = 12 + 2 * 6 = 12 + 12 = 24

a = 24 / 4 * 2 = 6 * 2 = 12

5) a := 3;

b := 8 + 2 * a;

a := b / 2 * a.

a = 3

b = 8 + 2 * 3 = 8 + 6 = 14

a = 14 / 2 * 3 = 7 * 3 = 21

6) f := 21;

e := 10;

f := 5 * f + 5;

e := f – 10 – e * 5.

f = 21

e = 10

f = 5 * 21 + 5 = 105 + 5 = 110

e = 110 - 10 - 10 * 5 = 100 - 50 = 50

7) a := 14;

b := 4;

a := a / 2 - b;

b := (a * b) / 2;

b := a + b

a = 14

b = 4

a = 14 / 2 - 4 = 7-4 = 3

b = ( 3 * 4) / 2 = 12 / 2 = 6

b = 3 + 6 = 9

8) b := 5;

a := -3;

a := 7 + a * b;

b := a / 2 + b

b =5

a = -3

a = 7 + (-3 * 5) = 7 + (-15) = -8

b = -8/2 + 5 = -4 +5 = 1

9) a := 4;

b := 5;

a := b + 15;

b := 100 / a * 4.

a = 4

b = 5

a = 5 + 15 = 20

b = 100 / 20 * 4 = 5 * 4 = 20

10) b := 8;

a := 10;

b := b + a * 2;

a := 29 - a;

b = 8

a = 10

b = 8 + 10 * 2 = 8 + 20 = 28

a = 29 - 10 = 19;

Объяснение: