Составить программу вычисления в одномерном массиве с произведения четных и положительных элементов и сумму элементов меньших 6

Var
  c:array [1..10] of integer;
  i, even, positive, sumLessSix: integer;
begin
  randomize;
  writeln ('Рандомный массив');
  for i:=1 to 10 do begin
    c[i]:= random(20)-10;
    write (c[i],' ');
  end; {for}
  writeln;
  writeln('Произведение четных чисел');
  even:=1;
  for i:=1 to 10 do
    if c[i] mod 2 = 0  then
    even:= even*c[i];
  write(even,' ');
  writeln;
  writeln('Произведение положительных чисел');
  positive:=1;
  for i:=1 to 10 do
    if c[i] > 0 then
    positive:= positive*c[i];
  write(positive,' ');
    writeln;
  writeln('Сумма элементов меньших 6');
  positive:=1;
  for i:=1 to 10 do
    if c[i] < 6 then
    sumLessSix:= sumLessSix+c[i];
  write(sumLessSix,' ');
end.

#include

#include

#include

#include

#include

#include

typedef struct

{

char imya[40];

char familiya[40];

char otchestvo[40];

int telefon;

int texpasport;

float pages ;

}gor;

void form(char mass[10], char *imya, char *familiya, char *otchestvo, int telefon, int texpasport)

{

file *f;

gor y;

int i;

if ((f=fopen(mass,"w"))==null) exit(1);

for (i=1; i< =3; i++)

{

cout< < "vvedite imya: ";

cin> > imya;

cout< < "vvedite familiya: ";

cin> > familiya;

cout< < "vvedite otchestvo: ";

cin> > otchestvo;

cout< < "vvedite telefon: ";

cin> > telefon;

cout< < "vvedite texpasport: ";

cin> > texpasport;

fwrite(& y,sizeof(gor),1,f);

if(ferror(f)! =null)

exit(2);

}

fclose(f);

}

void vivod(char mass[50])

{

file *f;

gor z;

if ((f=fopen(mass, "r"))==null) exit(3);

cout< < "fail: "<

while (! feof(f)) {

fread (& z,sizeof(gor),1,f);

if (! feof(f))

{

cout< < "imya: "<

cout< < "familiya: "<

cout< < "otchestvo: "<

cout< < "telefon: "<

cout< < "texpasport: "<

}

fclose(f);

}

}

void del(char fo[10], char fi[10])

{

file *f1,*f2;

gor d;

//char temp[40];

if ((f1=fopen(fi,"r"))==null) exit(4);

if ((f2=fopen(fo,"w"))==null) exit(5);

//cout < < "vvedite nazvanie na ydalenie - ";

//cin > > temp;

for (int i=0; i< 3; i++)

{

fread(& d,sizeof(gor),1,f1);

if (feof(f1)) break;

if (i> 2)

fwrite (& d,sizeof(gor),1,f2);

}

fclose(f2);

fclose(f1);

}

void dobav(char fi[10], char fo[10],char *imya, char *familiya, char *otchestvo, int telefon, int texpasport)

{

int q;

int i;

gor d;

file *f1,*f2;

char temp[40];

if ((f1=fopen(fi, "r"))==null) exit(4);

if ((f2=fopen(fo,"r+"))==null) exit(5);

cout < < "vvedite familiu, pered kotorym nuzno dobavit element: ";

cin > > temp;

for (i=0; i< 10; i++)

{

fread(& d,sizeof(gor),1,f2);

if (feof(f2)) break;

if (strcmp(d.familiya, temp)) break;

q=i;

}

for (i=0; i< 10; i++)

{

if (feof(f2)) break;

fwrite (& d,sizeof(gor),1,f2);

if (i==q-1)

{

cout< < "vvedite imya: ";

cin> > imya;

cout< < "vvedite familiya: ";

cin> > familiya;

cout< < "vvedite otchestvo: ";

cin> > otchestvo;

cout< < "vvedite telefon: ";

cin> > telefon;

cout< < "vvedite texpasport: ";

cin> > texpasport;

cout <

}

}

fclose(f2);

fclose(f1);

}

void main()

{

int n=10;

//cout < < "vvedite kol-vo zapisey: - ";

//cin> > n;

//cout <

form("f1.txt",n);

vivod("f1.txt");

del("f1.txt","f2.txt");

cout < < "posle udalenia: \n";

vivod("f2.txt");

getch();

n=1;

system("cls");

dobav ("f2.txt","f2.txt");

cout < < "posle dobavlenia: \n";

vivod ("f2.txt");

getch();

}

s = 45

Объяснение:

s = 100 // s = 100

for k in range(11): // Цикл выполняется 11 раз (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

   s = s - 5; // s = s - 5

print(s) // Выводим s

Итерация 1:

s = 100

s = 100 - 5

s = 95

Итерация 2:

s = 95

s = 95- 5

s = 90

Итерация 3:

s = 90

s = 90 - 5

s = 85

Итерация 4:

s = 85

s = 85- 5

s = 80

Итерация 5:

s = 80

s = 80- 5

s = 75

Итерация 6:

s = 75

s = 75- 5

s = 70

Итерация 7:

s = 70

s = 70- 5

s = 65

Итерация 8:

s = 65

s = 65- 5

s = 60

Итерация 9:

s = 60

s = 60- 5

s = 55

Итерация 10:

s = 55

s = 55- 5

s = 50

Итерация 11:

s = 50

s = 50 - 5

s = 45