Синформатикой, 100 , нужно подробное решение 1) переведите число 3591, 3581 в 16-тиричную систему счисления с точностью до 5 знаков после запятой. 2) сколькими можно составить пятизначное число из цифр 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 так, чтобы никакие две четные цифры не стояли рядом

Воть тебе оба задания, а так, теорию и на первое, и на второе, при желании можно найти в интернете.

Program gt2;
var i,j,s:integer;
a:array[1..4,1..4]of integer;
begin
randomize;
for i:=1 to 4 do
for j:=1 to 4 do
a[i,j]:=random(7)+12;
for i:=1 to 4 do
begin
s:=0;
for j:=1 to 4 do
s:=s+a[j,i];
writeln(s);
end;
end.

program gt3;
var i,j,s:integer;
a:array[1..7,1..7]of integer;
begin
randomize;
for i:=1 to 7 do
for j:=1 to 7 do
a[i,j]:=random(7)+12;
for i:=1 to 7 do
begin
s:=0;
for j:=1 to 7 do
if(a[j,i]<14)then s:=s+1;
writeln(s);
end;
end.

program gt4;
var i,j,p:integer;
a:array[1..3,1..3]of integer;
begin
for i:=1 to 3 do
for j:=1 to 3 do
read(a[i,j]);
for i:=1 to 3 do
begin
p:=a[i,1];
a[i,1]:=a[i,2];
a[i,2]:=p;
end;
for i:=1 to 3 do
begin
for j:=1 to 3 do
begin
write(a[i,j],' ');
end;
writeln;
end;
end.

VAR
i, j: Integer;
a: Array [1..10] of Array [1..10] of Integer;
BEGIN
for i := 1 to 10 do
for j := 1 to 10 do a[i][j] := j*j;

for i := 1 to 10 do begin
for j := 1 to 10 do Write(a[i][j],' '); Writeln; end;
END.

VAR
i, j: Integer;
a: Array [0..4] of Array [1..4] of Integer;
BEGIN
for i := 1 to 4 do
for j := 1 to 4 do begin
a[i][j] := Random(7)+12;
a[0][j] := a[0][j] + a[i][j];
end;

for i := 1 to 4 do begin
for j := 1 to 4 do Write(a[i][j],' '); Writeln; end;

Writeln;
for i := 1 to 4 do Write(a[0][i],' ');
END.

VAR
i, j: Integer;
a: Array [0..7] of Array [1..7] of Integer;
BEGIN
for i := 1 to 7 do
for j := 1 to 7 do begin
a[i][j] := Random(7)+12;
if (a[i][j] < 14) then Inc(a[0][j]);
end;

for i := 1 to 7 do begin
for j := 1 to 7 do Write(a[i][j],' '); Writeln; end;

Writeln;
for i := 1 to 7 do Write(a[0][i],' ');
END.

VAR
i, j: Integer;
a: Array [0..3] of Array [1..3] of Integer;
BEGIN
for i := 1 to 3 do
for j := 1 to 3 do Read(a[i][j]);

for i := 1 to 3 do begin
a[0][i] := a[1][i]; a[1][i] := a[2][i];
a[2][i] := a[0][i]; end;

for i := 1 to 3 do begin
for j := 1 to 3 do Write(a[i][j],' '); Writeln; end;
END.

VAR
i, j, m: Integer;
a: Array [1..5] of Array [1..5] of Integer;
BEGIN
for i := 1 to 5 do
for j := 1 to 5 do begin
a[i][j] := Random(5)+1;
end;

for i := 1 to 5 do begin
for j := 1 to 5 do Write(a[i][j],' '); Writeln; end;

m := 6;
for i := 1 to 5 do
for j := 1 to 5 do
if (i > j)and(m > a[i][j]) then m := a[i][j];

Writeln(a[i][j]);
END.