Фотоальбом полностью занимает dvd объёмом 4, 7 гбайт. сколько времени уйдёт на просмотр всех фотографий, если на просмотр одной фотографии уходит 7 с и каждая фотография занимает 300 кбайт? !
const n = 6; var a:array[1..n,1..n] of integer; i,j:integer; t:integer;
begin for i := 1 to n do for j := 1 to n do read(a[i,j]);
for j := 1 to n div 2 do for i := 1 to n do begin t := a[i,j]; a[i,j] := a[i,n+1-j]; a[i,n+1-j] := t; end;
for i := 1 to n do begin writeln; for j := 1 to n do write(a[i,j],' '); end end.
{2}
const n = 6; var a:array[1..n,1..n] of integer; i,j:integer; t:integer;
begin for i := 1 to n do for j := 1 to n do read(a[i,j]);
for i := 1 to n do for j := i+1 to n do begin t := a[i,j]; a[i,j] := a[j,i]; a[j,i] := t; end;
for i := 1 to n do begin writeln; for j := 1 to n do write(a[i,j],' '); end end.
diannaevaaa
18.11.2020
1) var i, j: integer; ar: array[1..6, 1..6]of integer; begin for i := 1 to 6 do for j := 1 to 6 do read(ar[i, j]); writeln; for i := 1 to 6 do swap(ar[i, 1], ar[i, 6]); for i := 1 to 6 do swap(ar[i, 2], ar[i, 5]); for i := 1 to 6 do swap(ar[i, 3], ar[i, 4]); for i := 1 to 6 do begin for j := 1 to 6 do write(ar[i, j], ' '); writeln; end; end. 2) var mr, rm: array [1..6, 1..6] of integer; i, j: integer; begin for i := 1 to 6 do for j := 1 to 6 do read(mr[i, j] ); for i := 1 To 6 do for j := 1 To 6 do rm[i, j] := mr[j, i]; writeLn; for i := 1 to 6 do begin for j := 1 to 6 do write(rm[i, j],' '); writeln; end; readln; end.
113 секунд для просмотра 16 фотографий