№1. логические выражения: ( форму имеет выражение, в котором отсутствует двойное отрицание и знаки отрицания находятся только над логическими переменными.) 1. 1+а·0= 2. х·х·1= 3. 0·х+0= 4. 0+х·1= 5. в·(а + (а·в))= 6. (а + с) · (а + с) · (в + с) = 7. (а·в) + а·в + а·в + в·с= 8. d + a·b·c·(b+c) =

11010000101000011101000010111010110100001011111011010001100000001101000010111110001000001101000010111101110100001011000011010001100000011101000110000010110100011000001111010000101111111101000010111000110100011000001000100000110100001011110111010000101111101101000010110010110100011000101111010000101110010010000011010000101100111101000010111110110100001011010000101110001000001101000010011101110100001011000000100000110100001001110111010000101111101101000010110010110100011000101111010000101110010010000011010000101100111101000010111110110100001011010000100000110100001011101111010001100011101101000010110100110100001011100000100000110100001011010011010000101100001101000110000000110100011000111111010001100000100010000011010000101101001101000110000000110100011000001111010000101100110010000011010000101101001101000110000000110100011000001111010000101100111101000110000011001000001101000010111111110100001011111011010000101101001101000010110000110100011000000011010000101110101101000010111000001011100010000011010000100101001101000010110101110100001011010000100000110100001001110011010000101111101101000110000000110100001011111011010000101101110010000011010000101111111101000010111110110100001011010011010000101100001101000110000000110100001011100011010000101110110010000011010000101111001101000010111101110100001011010100100000110100001011110111010000101100000010000011010000100111011101000010111110110100001011001011010001100010111101000010111001001000001101000010110011110100001011111011010000101101000010000011010001100000001101000010110000110100001011010011010000101110001101000010111110110100011000001111010000101111111101000110000000110100001011000011010000101100101101000010111011110100011000111111010000101101011101000010111100110100011000001111010001100011100010000011010000101111001101000010110000110100011000100011010000101110001101000010111101110100011000001100101110001000001101000010101111001000001101000010111011110100011000111011010000101100011101000010111011110100011000111000100000110100001011101011010001100000111101000110001000110100001011000011010001100000101101000110001100001000001101000010110000110100001011111111010000101101011101000010111011110100011000110011010001100000011101000010111000110100001011110111010001100010110010000011010000101111011101000010110000001000001101000010011101110100001011111011010000101100101101000110001011110100001011100100100000110100001011001111010000101111101101000010110100001011100010000011010000100111011101000010110000001000001101000010011101110100001011111011010000101100101101000110001011110100001011100100100000110100001011001111010000101111101101000010110100001000001101000010111000110100011000000111010000101111111101000010111110110100001011101111010000101111011101000110001111110100011000111011010001100000101101000110000001110100011000111100100000110100001011110011010000101101011101000110000111110100011000001011010001100010110010111000100000110100001001110111010000101100000010000011010000100111011101000010111110110100001011001011010001100010111101000010111001001000001101000010110011110100001011111011010000101101000010000011010000101111111101000110000000110100001011111011010000101110001101000110000001110100011000010111010000101111101101000010110100110100011000111111010001100000100010000011010001100001111101000110000011110100001011010011010000101101011101000110000001110100001011000000101110

вот удачи))

Задание 1:
Развернутая форма числа - представление числа в виде суммы каждого разряда числа.

4563 = 4 × 10^3 + 5 × 10^2 + 6 × 10^1 + 3 × 10^0

100101 = 1 × 2^5 + 0 ×2^4 + 0 ×2^3 + 1 ×2^2 + 0 ×2^1 + 1 ×2^0

AC6 = 10 ×16^2 + 12 ×16^1 + 6 × 16^0

Задание 2:

1001010, 112, 4А

Задание 3:

1)

11001101011+1110000101=100111110000
101011-10011=11000
1011х101=101100+1011=110111

2)

+564
  234

1020

Получилось: 564+234 = 1020

-652
 465

 165

Получилось: 652-465 = 165

3)

+DF45
 128A

F1CF

Получилось: DF45+128A = F1CF

-92D4
 11AE

8126

Получилось: 92D4-11AE = 8126