k: =0; m: =0; for i: =1 to 40 do beginif (a[i]> 99) and (a[i]< 1000) and (a[i]mod2< > 0) thenk: =k+1; m: =m+a[i]; end; writeln(m/k); end.
annarom1306
11.04.2022
1) var i,a,b: longint; begin read(a,b); for i: =a to b do if (i mod 3=0) then write(i,' '); writeln; end. 2) var i: longint; begin for i: =10 to 99 do if (abs(i mod 10 - i div 10)< =1) then write(i,' '); writeln; end. 3) var i,s,f,t: longint; begin for i: =100 to 999 do begin f: =i div 100; s: =i div 10 mod 10; t: =i mod 10; if (f=s) or (f=t) or (s=t) then write(i,' '); end; writeln; end.
Людмила902
11.04.2022
Var a, n, ch, nch, i: integer; begin write("n: "); readln(n); ch: =1; nch: =0; for i: =1 to n do begin read(x); if x mod 2=0 ch: =ch*x; else nch: =nch+x; end; if ch=1 ch: =0; writeln("произведение чётных: ", ch, "; сумма нечётных: ", nch, "."); end. var i, n, o, p, x: integer; begin write("n: "); readln(n); p: =0; o: =0; for i: =1 to n do begin read(x); if x> 0 inc(p); if x< 0 inc(o); end; write("кол-во положительных чисел: ", p, "; кол-во отрицательных чисел: ", o, ". разница: ", abs(p-o)); end.
k: =0; m: =0; for i: =1 to 40 do beginif (a[i]> 99) and (a[i]< 1000) and (a[i]mod2< > 0) thenk: =k+1; m: =m+a[i]; end; writeln(m/k); end.