muzaffarovich-Sergei1777
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Ввашем распоряжении только два вещества: вода и литий. у вас есть практически любое оборудование , которое может понадобиться. напишите уравнение всех возможных реакций, которые можно осуществить исходя из названных веществ с целью получения как можно большего числа новых веществ.

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Gpack54
2li + 2н2о = 2lioh + h2 - получили гидроксид лития и водород; 2н2о , > 2н2 + о2 - получили кислород; 3о2 > 2о3 - получили озон; 2li + h2 °> 2lih - получили гидрид лития; 4li + o2 = 2li2o - получили оксид лития; 2li2o + o2 °, > 2li2o2 - получили пероксид лития; li2o2 + 2h2o °> 2lioh + н2о2 - получили перекись водорода; li2o2 + o2 °, p, > 2lio2 - получили надпероксид лития; h2o2 (безв.) + o3 °> h2o3 (малые количества) + o2 - получили триоксид водорода;
gelena03
2li+h2o= li2o+h2 2li+h2o=2lioh + h2o при температуре
borzhemskaya19823110
  х г                                                                       336 л   zn           +               2hcl       ->       zncl2     +     h2 n=1 моль                                                             n=1 моль м = 65 г/моль                                                   vm=22,4 л/миоль m=65 г                                                               v = 22,4 л х г zn     -     336 л н2 65 г zn   -     22,4 л н2 m(zn) = 65 * 336 / 22,4 =975 г
idalbaev
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Ввашем распоряжении только два вещества: вода и литий. у вас есть практически любое оборудование , которое может понадобиться. напишите уравнение всех возможных реакций, которые можно осуществить исходя из названных веществ с целью получения как можно большего числа новых веществ.
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