Вычислите массу соли , образовавшуюся при взаимодействии 80г оксида меди 2 с соляной кислотой помгите

Решение: 2hcl+cuo=cucl2+h2o m(cuo)=80г/моль n(cuo)=n(cucl2)=80/80=1моль m(cucl2)=134г/моль m=n*m m(cucl2)=1*134=134г ответ: 134г

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  х г                                                                       336 л   zn           +               2hcl       ->       zncl2     +     h2 n=1 моль                                                             n=1 моль м = 65 г/моль                                                   vm=22,4 л/миоль m=65 г                                                               v = 22,4 л х г zn     -     336 л н2 65 г zn   -     22,4 л н2 m(zn) = 65 * 336 / 22,4 =975 г