Опрделите массу 2 молей соляной кислоты hcl

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Объяснение:

1) Составим уравнение реакции:

K_2$CO_3$ плюс Ba(NO_3)_2$ = BaCO_3$\downarrow плюс 2$KNO_3

2) Рассчитаем массу и количество вещества нитрата бария в растворе:

m(Ba(NO_3)_2)=m_(p минус pa) умножить на дробь, числитель — \omega, знаменатель — 100 =17,4 умножить на 0,15=2,61 $г;

n(Ba(NO_3)_2$)=m(Ba(NO_3)_2)/$M(Ba(NO_3)_2)=2,61 : 261=0,01 $моль.

3) Определим массу вещества, выпавшего в осадок:

по уравнению реакции n(BaCO_3$)= n(Ba(NO_3)_2$)=0,01 моль;

m(BaCO_3)=0,01 умножить на 197=1,97 г.