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При сгорании некоторой порции ув получено 0, 3 моль воды и 0, 4 моль оскида углерода(iv определите молекулярную формулу углеводорода , если его плотность при н.у. равна 2, 41 г/л.

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svetkaiv
Решение см во вложении
При сгорании некоторой порции ув получено 0,3 моль воды и 0,4 моль оскида углерода(iv). определите м
juliajd

4P+5O =2PO

PO +3HO = 2HPO

2HPO+ 3CaO = Ca(PO)+3HO

2HO+2Na = 2NaOH+ H

3NaOH + HPO = NaPO + 3HO

7. Si +O = SiO

SiO + 2NaOH = NaSiO + H2O

NaSiO + 2HCl = 2NaCl + HSiO

HSiO = SiO + HO

SiO+ LiO = LiSiO

8. 2 Ca + O = 2CaO

CaO + CO = CaCO

CaCO + 2HCl =CaCl + CO + HO

CaCl + 2NaOH = Ca(OH) +2NaCl

Ca(OH) + NaCO = CaCO + 2NaOH

9. NO + HO = 2HNO

2HNO+ CaO = Ca(NO) + HO

Ca(NO) + NaCO = CaCO + 2NaNO

CaCO + 2KNO = Ca(NO) + KCO

Ca(NO)+ Ba(OH) = Ca(OH) + Ba(NO)

10. Mg(OH) = MgO + HO

MgO + NaCO = MgCO + NaO

MgCO + 2HCl = MgCl + CO + HO

MgCl + 2KNO = Mg(NO) + 2KCl

3Mg(NO) + 2NaPO = Mg(PO) + 6NaNO

manuchar-formen2

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При сгорании некоторой порции ув получено 0, 3 моль воды и 0, 4 моль оскида углерода(iv определите молекулярную формулу углеводорода , если его плотность при н.у. равна 2, 41 г/л.
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