Опишите опыт резерфорда про радиоактивность!!

дано

m(CxHyOz) = 11.5 g

V(CO2) = 5.6 L

m(H2O) = 4.5 g

D(возд) = 1.59

CxHyOz-?

M(CxHyOz) = D()* 29 = 1.59 * 29 = 46.11 g/mol

n(C) = n(CO2) = V/Vm = 5.6 / 22.4 = 0.25 mol

n(H) = 2*n(H2O) = 2*(m(H2O) / M(H2O)) = 2*( 4.5 / 18) = 0.5 mol

M(C) = 12 g/mol

m(C) = n(C)*M(C) = 0.25 * 12 = 3 g

M(H) = 1 g/mol

m(H) = n(H)*M(H) = 0.5 * 1 = 0.5 g

m(O) = m(CxHyOz) - (m(C)+m(H)) = 11.5 - (3+0.5) = 8 g

M(O) = 16 g/mol

n(O) = m(O) / M(O) = 8 / 16 = 0.5 mol

n(C) : n(H) : n(O) = 0.25 : 0.5 : 0.5 = 1:2:2  

CH2O2  ==> HCOOH

ответ : Муравьиная кислота

1. CuO+H2=Cu+H2O

Cu{2+} + 2e- =Cu{0} | 1

H2{0} - 2e- =2H{+} | 1

2. 3H2+N2=2NH3

H2{0} - 2e- = 2H{+} | 3

N2{0} + 3e- = 2N{3} | 2

3. 4Al+3O2=2Al2O3

Al{0} - 3e- = Al{3+}. | 4

O2{0} + 4e- = 2O{2-} | 3

4. 2KMnO4=K2MnO4+MnO2+O2

Mn{7+} + e- = Mn{6+}. |1

Mn{7+} + 3e- = Mn{4+} |1

2O{2-} - 4e- = O2{0}. |1

5. 2NaNO3=2NaNO2+O2

N{5+} + 2e- = N{3+}. |2

2O{2-} - 4e- = O2{0} |1

6. 4NH3+5O2=4NO+6H2O

N{3-} - 5e- = N{2+}. |4

O2{0} + 4e- = 2O{2-} |5

7. 4NH3+3O2=2N2+6H2O

2N{3-} - 6e- = N2{0} |2

O2 + 4e- = 2O{2-}. |3

8. 8Na++10HNO3=8NaNO3+NH4NO3+3H2O

(тут ошибка в уравнении - не О2, а Н2О в продуктах)

Na{0} - e- = Na{+}. |8

N{5+} + 8e- = N{3-} |1