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Рассчитать массу железа, которым можно получить из 480 г. оксида железа (3) при восстановлении его оксидом углерода (2), если массовая доля выхода железа составляет 95 %

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Ответы

mariokhab

fe2o3+co=2fe+co2+o2

m(f2o3)=56*2+16*3=160г/моль

m(fe)=56г/моль

m(fe)=(480*56*2)/160=336г

m(fe)=336*0.95=319.2г - ответ

Сорокина

fe2o3+co=2fe+co2+o2

m(f2o3)=56*2+16*3=160г/моль

m(fe)=56г/моль

m(теоретическая)(fe)=(480*56*2)/160=336г

m(практическая)(fe)=336*0.95=319.2г

ответ: 319.2г

 

 

 

 

 

 

 

 

 

 

Шарабанов
Есть простая формула, которую надо запомнить. m/m = v = n/na, гдеm - масса образца вещества в граммахm - молярная масса вещества в граммах/моль - численно равна сумме относительных атомных масс в молекуле вещества, которые надо взять из таблицы менделееваv - количество вещества в моляхn - количество частиц (молекул или атомов) в образце веществе в штукахna - константа - количество частиц вещества в 1 моле вещества в штуках - найти в учебнике или инете значение. по этой формуле можно перейти от массы вещества к количеству вещества или к количеству частиц в веществе. -- найти число атомов в алюминиевом предмете массой 135 грамм -- атомный вес алюминия - 27, значит 1 моль алюминия весит 27 г. в 135 г содержится 5 молей, а в каждом моле число авогадро - n = 6*10^23 атомов. всего 30*10^23 = 3*10^24 атомов.
kate281078

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Рассчитать массу железа, которым можно получить из 480 г. оксида железа (3) при восстановлении его оксидом углерода (2), если массовая доля выхода железа составляет 95 %
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