Окружность с радиусом 1 разбита на три дуги так что величины соответствующих им центральных углов пропорциональны числам 1 2 и 3 найдите длину наибольшей дуги

L=2πr=6.28*1=6.28мдлина всей 1+2+3=6 частей всего 6,28: 6≈1,04м одна часть 1,04*3=3,12м  длина большей дуги

Все эти углы центральные. длину окружности можно измерять в градусах. 1+2+3=6(частей) 360: 6=60 градусов-одна часть, или меньшая дуга 60 *2=120 градусов средняя дуга 60*3=180  градусов  -наибольшая дуга

My summer holidays (мои летние каникулы) after my hard and busy school year my summer holidays began. i felt happy and began to plan a lot of wonderful things to do during my summer vacation.   i was dreaming about far south countries i always wanted to visit but i had to go to the azove seaside with my relatives. the water was very warm there because you know azove sea isn’t deep. what i liked there - a lot of different kinds of entertainment there: "water mountains", water scooters and discos. there was nothing to do all day except lying in the sun and getting a wonderful tan. i was playing with my little sister on the sand and in the waves teaching her to swim. later i returned to kherson and spent some time in town going out with my friends, reading, listening to music, watching tv, playing computer games. after that i went to the sports camp where i spent seven days. it was very useful experience because i had to get up very early, to train a lot, and to rest very little. but it made me stronger and healthier. i was very happy to return home and i spent several days in my summer cottage, i helped my grandpa to dig the garden, to water plants, and to gather fruit and vegetables. i was fishing with my grandpa and we were cooking fish together. only insects were spoiling my good mood. i enjoyed floating by boat, swimming in the river and helping my grandparents. during my summer holidays i made many new friends, read a lot of interesting books, got to know a lot of useful things. now i feel ready to get back to school. i am happy to meet my friends and teachers. чуть чуть можешь переделать)

По условию, рассматриваются такие пары чисел m=7a и n=7b, что числа a и b взаимно просты, а произведение чисел m и n  равно 2940. тогда (7a)*(7b)=49ab=2940 и ab=60=2²*3*5. будем считать, что a< b и переберем всевозможные варианты: a=1, b=60 — m=7, n=420, m+n=427 случай a=2, b=30 невозможен, так как числа a и b должны быть взаимно просты. аналогично, невозможен случай a=6, b=10 a=3, b=20 — m=21, n=140, m+n=161 a=4, b=15 — m=28, n=105, m+n=133 a=5, b=12 — m=35, n=84, m+n=119 таким образом, наименьшая возможная сумма равна 119.