Решите уравнение: 1) x^4 - 3x^2 + 2 = 0 2) x^4 - 9x^2 - 10 = 0

1)а) 2m-4m+5n = - 2m + 5n б)3m-2n нельзя в) -1,3a+4a-3,7a = -  a г) 4x-8y-6x+11y = - 2x + 3y 2)a) -7x  -  8x+2x = - 13x б) -1,5a+7,3b  нельзя в) 1,8b  -  5,8b  +  3b = - b г) -2m  +  3n  -  8m  -  n  =   2n - 10m 2. выражение:   1)а) (a  -  2)  +  (a  -  3)  -  (-2a+7) = a - 2 + a - 3 + 2a - 7 = 4a - 12 б) 2•(а-+6) = 2a - 6 - 5a - 6 = - 3a - 12 в) -3•(2x-9)+(-5x+1) = - 6x + 27 - 5x + 1 = - 11x + 28 2) a) (x-3)+(x-5) -  (7-3x) = x - 3 + x - 5 - 7 + 3x = 5x - 15 б) -2•(m-3)  -  (3m-5) = - 2m + 6 - 3m + 5 = - 5m + 11 в) 4•(2a-1)+(7-5a) = 8a - 4 + 7 - 5a = 3a + 3

(-∞;-1) ∪ (;+∞)

Объяснение:

0\\D=49+4*12*19=961\\x1= \frac{7-31}{24} =-1\\x2=\frac{7+31}{24} =\frac{38}{24} =\frac{19}{12}" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=12x%5E2-7x-19%3E0%5C%5CD%3D49%2B4%2A12%2A19%3D961%5C%5Cx1%3D%20%5Cfrac%7B7-31%7D%7B24%7D%20%3D-1%5C%5Cx2%3D%5Cfrac%7B7%2B31%7D%7B24%7D%20%3D%5Cfrac%7B38%7D%7B24%7D%20%3D%5Cfrac%7B19%7D%7B12%7D" title="12x^2-7x-19>0\\D=49+4*12*19=961\\x1= \frac{7-31}{24} =-1\\x2=\frac{7+31}{24} =\frac{38}{24} =\frac{19}{12}">

(x+1)(x-)>0

(-∞;-1) ∪ (;+∞)