moskvichkabakery56
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Найдите корни уравнения 1) (x + 1)(2x - 3)=7 2)x(3x - 2) = (5x + 2 )( x-1) 3) ( x - 8 )(x - 9) + 52 = 0 4) x( x+7 )=( 2-x )( x+2)

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Ответы

rstas
1) 2x^2-3x+2x-3=7; 2x^2-x-10=0; D=1+4×2×10=81; x1=(1+9)/4=10/4; x2=(1-9)/4=-2;
2)
zorinka777
Проведем отрезки OB и OC, как показано на рисунке.
Расстоянием от точки до прямой является длина перпендикуляра, проведенного к прямой. Поэтому, OE перпендикулярен AB, а OF перпендикулярен CD. Точки E и F делят свои хорды пополам (по свойству хорды)
Получается, что треугольники OEB и OCF - прямоугольные, EB=AB/2 и CF=CD/2.
По теореме Пифагора:
OB2=OE2+EB2
OB2=242+(20/2)2
OB2=576+100=676
OB=26
OB=OC=26 (т.к. OB и OC - радиусы окружности)
По теореме Пифагора:
OC2=CF2+FO2
OC2=(CD/2)2+FO2
262=(CD/2)2+102
676=(CD/2)2+100
(CD/2)2=576
CD/2=24
CD=48
ответ: CD=48
anton

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Найдите корни уравнения 1) (x + 1)(2x - 3)=7 2)x(3x - 2) = (5x + 2 )( x-1) 3) ( x - 8 )(x - 9) + 52 = 0 4) x( x+7 )=( 2-x )( x+2)
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