Триганометрические, составитель ошибся
а)sin x = ✓3/2
x = (-1)ⁿ π/3 + πn
б)cos x = -3/5
x = ±arccos(-3/5) + 2πk
x = ±(π-arccos(3/5)+2πk
в)2cos²x+cosx - 1 = 0
cos x = t
2t²+t-1 = 0
Так как a-b+c = 0(2-1-1 = 0):
t1 = -1
t2 = -c/a = 1/2
1)cos x = -1
x = π+2πn
2)cos x = 1/2
x = ±π/3 + 2πn
г)sinx + sin 3x + sin 5x = 0
sin3x + sin5x + sinx = 0
sin3x + 2sin3x • cos2x = 0
sin3x(1+2cos2x) = 0
1)sin 3x = 0
3x = πk
x = π/3 k
2)1+2cos2x = 0
2cos2x = -1
cos2x = -1/2
2x = ±(π-arccos(1/2) + 2πk
x = ±1/2(π-π/3)+πk
x = ±1/2(2π/3)+πk
x = ±π/3 + πk
1,(18)=1+0,(18)
0,(18)=x
18,(18)=100x
18+0,(18)=100x
18+x=100x
18=99x
x=18/99
x=2/11
0,(18)=2/11
1,(18)=1+0,(18) =1+2/11=13/11
2,(27)=7+0,(27)
0,(27)=x
27,(27)=100x
27+0,(27)=100x
27+x=100x
27=99x
x=27/99
x=3/11
0,(27)=3/11
1,(27)=1+0,(27) =1+3/11=14/11
0,(13)=x
13,(13)=100x
13+0,(13)=100x
13+x=100x
13=99x
x=13/99
0,(13)=13/99
2,(23)=7+0,(23)
0,(23)=x
23,(23)=100x
23+0,(23)=100x
23+x=100x
23=99x
x=23/99
x=23/99
0,(23)=23/99
2,(23)=2+0,(23) =2+23/99
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Разложить на множители: -20x²y³-5x⁴y