ответ: area between | y = sin(x)\nx = -pi\/6\nx = pi\/6
Result:
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integral_(-pi\/6)^(pi\/6) abs(sin(x)) dx = 2 - sqrt(3)~~0.267949.
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Найдите площадь фигуры, ограниченной линиями y=sinx, x=-π/6, x=π/6
ответ: area between | y = sin(x)\nx = -pi\/6\nx = pi\/6
Result:
More digits
Need a step by step solution for this problem? >>
integral_(-pi\/6)^(pi\/6) abs(sin(x)) dx = 2 - sqrt(3)~~0.267949.