2sin x cos x +√2 sin x - 2 cos x - √2 = 0 sin x(2cos x + √2) - ( 2cos x +√2) = 0 (2cos x + √2)(sin x -1) = 0 2cos x +√2 = 0 или sin x -1 = 0 2cos x = -√2 sin x = 1 cos x = -√2/2 x = π/2 + 2πn, n∈z x = +-arccos (-√2/2) + 2πк, к∈z x = +- 3π/4 +2πk , k∈z
ответ:
а: 0
объяснение:
√4=2
√9=3
√25=5
2х+3х-5х=0