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Бісектриса гострого кута паралелограма ділить його сторону на відрізки 5 см і 9 см, починаючи від вершини тупого кута. Висота паралелограма, проведена до цієї сторони, дорівнює 2 см. Знайди другу висоту паралелограма Рисунка не было, только задача)))​

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alzheleshikov

Дано: АВСВ - паралелограм, Р=48 см., СМ - бісектриса,  DM : MA = 5 : 2. Знайти АВ=СD,  AD=BC.

∠BCM=∠MCD за умовою

∠CMD=∠МСВ як внутрішні різносторонні при АD║ВС та січній  СМ, отже

∠CMD=∠MCD,  ΔMCD - рівнобедрений,  СD=MD.

Нехай АМ=2х см,  МD=5х см,  СD=5х см,  ВС=2х+5х=7х см,  АВ=5х см.

2(5х+7х)=48

12х=24;  х=2.

АВ=СD=5*2=10 см,  AD=BC=7*2=14 см.                                                                                                                                                                                                                                                                                    


мне с дз ❤️❤️ Бісектриса кута C Паралелограма ABCD Ділить сторону AD На відрізки DM іMA так що DM :
hrviko

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Бісектриса гострого кута паралелограма ділить його сторону на відрізки 5 см і 9 см, починаючи від вершини тупого кута. Висота паралелограма, проведена до цієї сторони, дорівнює 2 см. Знайди другу висоту паралелограма Рисунка не было, только задача)))​
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