4. 10. как расположена прямая относительно окружности, если диаметр окружности равен 16 см, а расстояние от цен-тра до прямой равно: 1) 7 см; 2) 8 см; 3) 9 см ! начертите​

Дано: треугольник авс ,ав=вс,р=32 см , ас  >   ав на 5 см найти: ав,вс решение : 1)пусть ав и вс = х ,то ас = х+5                 2)р=ав+вс+ас,32=х+х+х+5                     3х+5=32                     3х=5+32                     3х=27                     х=9 см - ав,вс ответ: 9 см.

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