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i7aster26

вот перевод надеюсь .

Roman913

15°, 150° и 15°

Объяснение:

Треугольник ABN - равносторонний, т.е. AB=AN=BN

Но ABCD - квадрат => AB=AN=BN=BC=CD=AD

Рассмотрим треугольник ADN:

<A=90°-<BAN = 90°-60° =30°

AD=AN => треугольник ADN - равносторонний

Значит, <ADN=<AND=(180°-30°)/2 = 75°

Рассмотрим треугольник BCN:

<B=90°-<ABN = 90°-60° =30°

BC=BN => треугольник BCN - равносторонний

Значит, <BNC=<BCN=(180°-30°)/2 = 75°

Рассмотрим треугольник DNC:

<CDN = 90°-<ADN = 90°-75° = 15°

<DCN = 90°-<BCN = 90°-75° = 15°

<DNC = 360° -<AND-<ANB-<BNC = 360°-75°-60°-75° = 150°

dashafox8739
Пусть о - центр окружности, описанной около треугольника аbc. тогда ∠boc=2∠bac=50°=∠bdc. значит d лежит на окружности, описанной около треугольника boc. аналогично, ∠boa=2∠bca=100°=∠bda. значит d лежит на окружности, описанной около треугольника boa, а значит d - одна из двух точек пересечения этих окружностей, которые есть о и b. очевидно, что d совпадать с b не может, значит d совпадает с о. т.е. d - центр окружности, описанной около abc. отсюда bdc - равнобедренный, ∠dbc=(180°-50°)/2=65° и значит угол между диагоналями abcd равен 180°-∠dbc-∠bca=180°-65°-50°=65°.

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