Втреугольнике abc угол c=90 градусов. ac=5, bc=5/корней из 3. найди sinb

треугольник прямоугольный, т.к угол = 90 градусам.

соs острого угла треугольника это отношение ac к ав

нужно найти ав по теореме пифагора

катеты известны: ac = 5, bc = 5корней из 3 тогда по теореме пифагора: 5в кв.+(5корней из 3)в кв.= abв кв.25+75=abв кв.ab =10 значит cos(a )= ac/ab= 5/10 = 0.5

1,по т. пифагора ав=корень из (ас^2+св^2)=корень из (25+75) = корень из 100=10 см

2, по теореме синусов ав/sinс=ас/sinв, выражаем sinb=ас*sinc/ав=(5*1)/10=1/2

угол в=30 гроадусов

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1. <ACB = 70°

2. <FED = 90°, <EFD = 70°

3. <MKL = 70°, <MLK = 70°

4. <NPO = 30°, <ONP = 120°

5. <B = 90°, <CAB = 45°, <ACB = 45°

6. <C = 60°, <B = 60°, <A = 60°

7. <ACB = 100°

8. <BAF = 30°, <ABF = 80°

9. <DAC = 40°, <CDA = 40°

10. <CDE = 110°, <DEC = 35°, <DCE = 35°

Объяснение:

1. <ACB = 180° - (50° + 60°) = 70°

2. <FDE = 90° => <EFD = 90° - 20° = 70°

3. MK = ML => треугольник равнобедренный => <MKL = <MLK = (180° - 40°) : 2 = 70°

4. PN = ON => треугольник равнобедренный => <NOP = <NPO = 30°

<ONP = 180° - (30° + 30°) = 120°

5. <B = 90°, AB = BC => труегольник прямоугольный и равнобедренный => <CAB = <ACB = 90° : 2 = 45°

6. тругольник CDE равносторонний => <C = <D = <E = 180° : 3 = 60°

7. <ACB = 180° - (40° + 40°) = 100°

8. <BAF и <BAC смежные => <BAF = 180° - 150° = 30°

<ABF = 180° - (70° + 30°) = 80°

9. <DAC и <BAC смежные => <DAC = 180° - 140° = 40°

AC = CD => треугольник равнобедренный => <DAC = <CDA = 40°

10. <CDE и <ADC смежные => <CDE = 180° - 70° = 110°

ED = DC => <DEC = <DCE = (180° - 110°) : 2 = 35°