On the right you'll see huge building​

ответ:

on the right you'll see a huge building

Using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace 1
{
class Program
{
static void Main(string[] args)
{
bool Mistake = false;
int N = 0;

do
{
Console.Write("Введите количество слагаемых: ");

try
{
N = Convert.ToInt32(Console.ReadLine());
Mistake = false;

}

catch (FormatException)
{
Mistake = true;

Console.Clear();
Console.WriteLine("Неверный формат ввода! Повторите попытку!");
Console.WriteLine();
}
}

while (Mistake == true);

Sum(N);
}

static void Sum(int N)
{
double[] Elements = new double[N];
double Result = 0;

for (int i = 0; i < N; i++)
{
Console.WriteLine();
Console.Write("Введите " + (i + 1) + " число: ");

try
{
Elements[i] = Convert.ToDouble(Console.ReadLine());
}

catch (FormatException)
{
Console.WriteLine("Неверный формат ввода!");
}
}

for (int j = 0; j < N; j++)
{
Result += Elements[j];
}

Console.WriteLine();
Console.Write("Сумма = " + Result);
Console.ReadKey();
}
}
}

C++

#include <iostream>#include <cstdlib>#include <ctime>using namespace std;int main(){ srand(time(0)); int mas[5][5]; int sum=0,sum1=0,sum2=0; for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ mas[i][j]=10+rand()%50; } } for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ if(i==j)sum+=mas[i][j]; if(i>j)sum1+=mas[i][j]; if(i<j)sum2+=mas[i][j]; } } for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ cout<<mas[i][j]<<" "; } cout<<endl; } cout<<endl; cout<<sum<<" "<<sum1<<" "<<sum2<<endl; return 0;}