O Дана последовательность операторов:а:=1;b:=2;while a+b<8 dobeginа

1.

Program u666;

Var

x, y, z, t, n, e, z1, z2, z3: real;

Begin

 readln (e, x, y);

 if sqrt (3*y)+x = 14

 then  

 begin

   z1:= Exp(3*x*y);

   z2:= x+3*y;

   z3:= 0.5*x;

   writeln (z1);

   writeln (z2);

   writeln (z3)

 end

 else

   z:= 0;

   writeln (z);

end.

2. Program Regret;

var x: integer;

begin

 read (x);

 if (x=1) or (x=3) or (x=5) or (x=7) or (x=8) or (x=10) or (x=12)

 then write ('31');

 if (x=4) or (x=6) or (x=9) or (x=11)

 then write ('30');

 if (x=2)

 then write ('28')

end.

Объяснение:

Интернет урок)

#define _CRT_SECURE_NO_WARNINGS

#include <iostream>

#include <ctime>

using namespace std;

int main()

{

 int y;

 char buffer[80];

 cout << "Year = ";

 cin >> y;

 tm time_in;

 time_in.tm_sec = 0;  // second

 time_in.tm_min = 0;  // minute

 time_in.tm_hour = 0; // hour

 time_in.tm_mday = 1; // 1-based day

 time_in.tm_mon = 9;  // 0-based month

 time_in.tm_year = y - 1900; // year since 1900

 time_t time_temp = mktime (&time_in);   // Convert the local time to a calendar value.

 tm* time_out = localtime (&time_temp);  // Converts a time_t time value to a tm structure

 if (time_out->tm_wday > 0)              // if it is not Sunday, go to the next Sunday

   time_out->tm_mday += 7 - time_out->tm_wday;

 

 strftime(buffer, 80, "%d.%m.%Y", time_out);  // date formatting for output

 cout << "\nTeachers day is " << buffer << "\n";

}

Объяснение: explanations in the comments to the program