За какое время по каналу с пропускной способностью 256 бит/с передадут 5 кбайт информации. ответ выразите в минутах

переводим 5 кбайт в биты:

5 * 1024 * 8 = 40 960 бит

находим время:

40 960 / 256 = 160 секунд

160 / 60 = 2,66 мин

ответ: 2,66 минуты.

uses crt; var i,j,k,n,m,t: integer; mas: array[1..10,1..10]of integer; begin randomize; readln(n); readln(m); writeln; writeln('bazovui massiv'); for i: =1 to m dofor j: =1 to n do mas[i,j] : =random(100); for i: =1 to m do beginwriteln; for j: =1 to n dowrite (mas[i,j],' '); end; writeln; for i: =1 to m dofor j: =1 to n do for k: =1 to n-1 do if mas[i,k]> mas[i,k+1] then begin t: =mas[i,k]; mas[i,k]: =mas[i,k+1]; mas[i,k+1]: =t; end; writeln; writeln('massiv posle obrabotki') ; for i: =1 to m do beginwriteln; for j: =1 to n dowrite (mas[i,j],' '); end; end.

uses crt; var i,j,k,n,m,t: integer; mas: array[1..10,1..10]of integer; begin randomize; readln(n); readln(m); writeln; writeln('bazovui massiv'); for i: =1 to m dofor j: =1 to n do mas[i,j] : =random(100); for i: =1 to m do beginwriteln; for j: =1 to n dowrite (mas[i,j],' '); end; writeln; for i: =1 to m dofor j: =1 to n do for k: =1 to n-1 do if mas[i,k]> mas[i,k+1] then begin t: =mas[i,k]; mas[i,k]: =mas[i,k+1]; mas[i,k+1]: =t; end; writeln; writeln('massiv posle obrabotki') ; for i: =1 to m do beginwriteln; for j: =1 to n dowrite (mas[i,j],' '); end; end.

на с++ как то так

#include< iostream> #include< ctime>

using namespace std;

int main(){ srand(time(null)); int n, a, sum = 0, ten = 10, index = 0; int *arr; cout < < "enter size of arr(enter n) : "; cin > > n; arr = new int [n]; for(int i = 1; i < = n; i++) arr[i] = rand()%25;

cout < < "arr : " < < endl; for(int i = 1; i < = n; i++) cout < < arr[i] < < " " ; cout < < endl;

cout < < "enter a : " ; cin > > a;

for(int i = 1; i < = n; i++) { if(arr[i] == a) index = i;

} if(index ! = 0) { for(int i = index + 1; i < = n; i++) sum = sum + arr[i]; } if(sum == 0) cout < < "result = " < < ten < < endl; else cout < < "result = " < < sum < < endl; }