keykov35
?>

Назовите продукты реакции zn=zno=znso4=zn(oh)2=zno

Химия

Ответы

mariy-inkina8

1. 2zn + o2 = 2zno (оксид цинка)

2. zno + h2so4 = znso4 (сульфат цинка) + h2o (вода)

3. znso4 + 2naoh = na2so4 (сульфат натрия) + zn(oh)2 (гидроксид цинка)

4. zn(oh)2 = zno (оксид цинка) + h2o (вода)

Мелконян1137

|̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿||̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳&#

Объяснение:

|̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿||̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳&#|̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊̿̿̿̿̊|̳̿||̳̿|||̳̿|̳̳̳̳̿̿̿̿l̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳̳&#

myrisik2490
29,4 г                 24 г me(oh)2     =     meo     +   h2o 1 моль               1 моль м=х+34 г/моль   м=х+16 г/моль n(me(oh)2) = m/m = 29,4/(x+34) моль n(meo) = 24/(x+16) моль по уравнению реакции n(me(oh)2) = n(meo) 29,4/(х+34) = 24/(х+16) 29,4х+470,4 = 24х + 816 5,4х = 345,6 х = 64 таким образом, молярная масса металла = 64 г/моль по таблице смотрим - это медь cu.

Ответить на вопрос

Поделитесь своими знаниями, ответьте на вопрос:

Назовите продукты реакции zn=zno=znso4=zn(oh)2=zno
Ваше имя (никнейм)*
Email*
Комментарий*

Популярные вопросы в разделе

airlineskozlova69
2 вариант решите 10 класс
vladimirkirv
zoosalon-hollywood5
Ионов202
Busyashaa
Татьяна
Валерия Воробьева396
mrubleva42
mmi15
barabanoveugeny
skorykin123371
Рожнов
oksana-popova
fotostock
andreyshulgin835