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P> p2o5 > h3po4 > k3po4 > ca3(po4)2 с цепочкой уравнений реакции

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ElenaSkvortsova2

2p+5co=5c+p2o5

p2o5+2h2o=h3po4+2h

lazaren-ko
7)a)нет, нельзя получить 8)c)да, образуется 12.8 г меди 9)a) fe fe(oh)2 10)d)4,48 11)a)1 4 512)сио + н2 = си + н2о      80                64находим количество вещества сио =8г/80г/моль =0,1моль находим количество вещества си по уравнению реакции1моль 1моль си0,1моль хмольси      х = 0,1моль синаходим массу си = 0,1моль*64г/иоль =6,4гсиответ :   a)   6,4 гси                        решение №10na2o +h2o = 2naoh62                      2*40находим количество веществаna2o=12,4г/62г/моль=0,2моль   находим количество вещества naoн по уравнению реакции 2моль0,          х =0,4моль naoн 2naoh + co2 = na2co3 + h2o находим количество вещества со2 по уравнению реакции 1мольсо20, со2          у =0.2моль со2найдем объем со2 =0,2моль*22,4л/моль =4,48л со2
gusinica23

Дур*

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