Решите по действиям г) 275, 4 : (22, 74 + 9, 66) * (937, 7 - 30, 6 * 30, 5)=?

1) 22,74+9,66=32,4
2) 30,6*30,5=933,3
3) 937,7-933,3=4,4
4) 275,4:32,4=8,5
5)8,5*4,4=37,4

1) -30,6 * 30,5 = 933,3
2) 937,7 - 933,3 = 4,4
3) 22,74 + 9,66 = 32,4
4) 275,4 : 32,4 = 8,5
5) 8,5 * 4,4 = 37,4

ответ: 37,4

x = -2.

ODZ: x belongs to [-2; 2].

Пошаговое объяснение:

In order to find the domain of definition of the function y = √ (4 - x ^ 2) (quadruple root), we start by considering it.

So, we are given a function whose variable is under the sign of the quadruple root.

In order for the function to have a value, the radical expression must be non-negative.

We need to find a solution to the following inequality:

4 - x ^ 2 ≥ 0;

We apply the formula difference of squares to the left side of the inequality:

(2 - x) (2 + x) ≥ 0;

Looking for points:

2 - x = 0;

x = 2;

2 + x = 0;

x = -2.

ODZ: x belongs to [-2; 2].

2x² -3x -9 =0 ;
2x² -6x +3x -9 =0;
2x(x-3) +3(x-3) =0 ;
(x-3)(2x+3) =0 ;
2(x+3/2)(x-3) =0 ⇒[ x+3/2=0 ;x-3 =0 ⇔[  x= - 3/2 ;x=3.
* * *x₁ =-3/2 ; x₂ =3.* * *

5 x²+3х+4=5(x² +(3/5)x +4/5 ) =5(x² +2*(3/10)x +(3/10)² -(3/10)² +4/5 ) =
=5 ((x +3/10)² +71/100) ≠0 →не имеет действительных корней.

3x² -2x-8 =3(x² -2*(1/3)*x +(1/3)² - (1/3)² -8/3) =3*((x-1/3)² -(5/3)²) =
3*(x-1/3 -5/3)(x-1/3 +5/3) =3*(x-2)(x +4/3) .
3x² -2x-8 =0 ⇔3*(x-2)(x +4/3) =0 x⇔[ x-2 =0 ;x +4/3=0⇔[ x=2 ; x = - 4/3.
* * *
3x² -2x-8 =(3x² -6x) +(4x -8) =3x(x-2) +4(x-2) =(x-2)(3x+4) =3(x+4/3)(x-2) .
3x² -2x-8 =0 ⇔3(x+4/3)(x-2) =0 ⇒ [x+4/3=0 ;x-2 =0 ⇔[x= - 4/3 ;x=2 .
* * * x₁ = - 4/3 ;x₂ =2 . * * *