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1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 1) 3х-5х= -13+3 2) 4х-7=2х+15 3) 7(2+у) – 3у=5у-6 4) 3(х-7)-(9-2х)=2(12-х)-(х-10) 5) 4(0, 6х-0, 3)-3(0, 7х-0, 1)=0 12. 1) -5у-17у=-50+6 2) 7х+12=10х-3 3) 4х-2(3+х)=9-х 4) 4(2-3х) – 2(9х-8)=15(1-х)+3(4-х) 5) 5(0, 14-0, 23х)+3(0, 3х+0, 1)=0 13. 1) -7х+12х=8-23 2) 33-5х=15-8х 3) 17+3(15-с)=(4-с)=(4-с)-2(с-5) 4) 7(3-х)-3(х-4)=5(3+2х)-2(-3-2х) 5) 0, 6(х-1)-(х+1)=0 14. 1) 16х – 7х= -42 – 39 2) -24+3х=9х+18 3) -3(5а-1)+4а=2а+7(5-3а) 4) 4(х-16) – (8-х)=10(х+1)-2(15+8х) 5) 5(0, 16х+0, 33) – (3-х)=0 15. 1) у-12у=-6-27 2) -15х+31=-7+4х 3) 2(4-9а) – (2а+3)= -8(4-а)+3(1+2а) 4) (х+2)+х=9 5) 1, 24х+3, 46=1, 76х+6, 58 16. 1) -22у-18у=5*(-2) 2) 11-х=55+х 3) 5(2-3в)-4(6+2в)=28-(в-2) 4) 2(х-2)+3=0, 4(х+8) 5) 5, 96-1, 8с=4, 7-2, 7с 17. 1) –х+6х= -45+15 2) 28-4х=19-х 3) -2(3х+4)+(6х+8)=4(5х-2)-(5х+8) 4) 2(5-3х)=6-5х 5) -4, 92у-(0, 08у+5, 12)= - 0, 88-у 18. 1) -27у-33у= - 12*(-5) 2) -35-2х=42+9х 3) 8(4-3у)-(7-2у)= -(6+3у)+8(у-2) 4) 11+2х=55+3х 5) -3(х-2)+4(1+2х)=10, 3+20х 19. 1) х+(7+х)=11 2) (х+8)+(3-2х)=3 3) 10(у-2)=9(у-6) 4) 3(1-х)-5(х+2)=1-4х 5) -15-3х= - 7х+45 20. 1) х+2х-5=40 2) 3х-1-(х+2)=1 3) -5(5-3у)=16(у-3) 4) (2+х)2+(4х-1)3=10х-7 5) -4(1+2х)+3(х-2)= -18, 3 – 20х 21. 1) х+(4+х)+х=16 2) (х-3)+(2х-4)= -1 3) 7(3у-5)= -10(3-2у) 4) (4+5х) – 3(2-х)=16х-0, 4 5) 8(4-3у)-(7-2у)= -(6+3у)+8(у-2) 22. 1) 4х-3+(1-х)= -2 2) 14(3у-2)= -7(4-6у) 3) 2х+0, 1 – 4(1-4х)=8х-4, 4 4) 6х+6=4х-2 5) 2, 44+2, 3р=3, 12+2, 7р 23. 1) 3(х-2)=х+2 2) (х+2)+(4х-3)-(5-х)=1 3) 4х-3=2х+1 4) -2х-4=2х+8 5) 0, 4(х-3)=0, 5(4+х)-2, 5 24. 1) 2(х-3)=7(2+х) 2) 3-(х+1)-(х-4)+(2х-1)=0 3) 2(1-х) – 4(2х+8)=8х+28 4) –(3у+7)=8-2(8-у) 5) 5, 96-1, 8с=4, 7-2, 7с

Математика

Ответы

rytikovabs
1) 3х - 5х = -13 + 3

To solve this equation, we need to combine like terms on each side of the equation.

On the left side of the equation, 3х and -5х are like terms since they both have the variable х. We can combine them by subtracting 5х from 3х, which gives us -2х.

On the right side of the equation, -13 and 3 are constants. Since they have no variables, they remain the same.

So, the equation becomes:
-2х = -10

To isolate х, we need to divide both sides of the equation by -2.

-2х / -2 = -10 / -2
х = 5

Therefore, the solution to the equation is х = 5.

2) 4х - 7 = 2х + 15

To solve this equation, we need to isolate the variable х by combining like terms and performing the necessary operations.

First, we can start by subtracting 2х from both sides of the equation:
4х - 2х - 7 = 2х - 2х + 15

Simplifying this equation gives us:
2х - 7 = 15

Next, we add 7 to both sides of the equation to isolate the term with х:
2х - 7 + 7 = 15 + 7

Simplifying this equation gives us:
2х = 22

Finally, we divide both sides of the equation by 2 to solve for х:
2х / 2 = 22 / 2
х = 11

Therefore, the solution to the equation is х = 11.

3) 7(2 + у) - 3у = 5у - 6

To solve this equation, we distribute the 7 to both terms inside the parentheses:
14 + 7у - 3у = 5у - 6

Next, we combine like terms on both sides of the equation.
On the left side:
14 + 7у - 3у can be simplified to 14 + 4у.

On the right side:
We already have 5у.

So, the equation becomes:
14 + 4у = 5у - 6

To isolate у, we need to move all terms containing у to one side of the equation. We do this by subtracting 5у from both sides:
14 + 4у - 5у = 5у - 5у - 6

Simplifying this equation gives us:
14 - у = -6

Next, we add у to both sides of the equation to isolate у:
14 - у + у = -6 + у

Simplifying this equation gives us:
14 = -6 + у

To solve for у, we subtract -6 from both sides of the equation:
14 - -6 = -6 - -6 + у

Simplifying this equation gives us:
20 = у

Therefore, the solution to the equation is у = 20.

4) 3(х - 7) - (9 - 2х) = 2(12 - х) - (х - 10)

To solve this equation, we need to simplify each side by distributing and combining like terms.

First, on the left side we distribute the 3 to both terms inside the parentheses and combine like terms:
3х - 21 - 9 + 2х = 2х - 24 - х + 10

Simplifying this equation gives us:
5х - 30 = х - 14

Next, we need to move all terms containing х to one side of the equation by subtracting х from both sides:
5х - х - 30 = х - х - 14

Simplifying this equation gives us:
4х - 30 = -14

Next, we add 30 to both sides of the equation to isolate the term with х:
4х - 30 + 30 = -14 + 30

Simplifying this equation gives us:
4х = 16

Finally, we divide both sides of the equation by 4 to solve for х:
4х / 4 = 16 / 4
х = 4

Therefore, the solution to the equation is х = 4.

5) 4(0.6х - 0.3) - 3(0.7х - 0.1) = 0

To solve this equation, we distribute and combine like terms on both sides.

On the left side:
4(0.6х - 0.3) can be simplified to 2.4х - 1.2
-3(0.7х - 0.1) can be simplified to -2.1х + 0.3

So, the equation becomes:
2.4х - 1.2 - 2.1х + 0.3 = 0

Next, we combine like terms on both sides of the equation.
On the left side:
2.4х - 2.1х can be simplified to 0.3х
-1.2 + 0.3 can be simplified to -0.9

So, the equation becomes:
0.3х - 0.9 = 0

To isolate х, we need to move the constant term (-0.9) to the other side of the equation by adding 0.9 to both sides:
0.3х - 0.9 + 0.9 = 0 + 0.9

Simplifying this equation gives us:
0.3х = 0.9

Finally, we divide both sides of the equation by 0.3 to solve for х:
(0.3х) / 0.3 = (0.9) / 0.3
х = 3

Therefore, the solution to the equation is х = 3.

I hope this explanation helps! Let me know if you have any further questions.

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1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 1) 3х-5х= -13+3 2) 4х-7=2х+15 3) 7(2+у) – 3у=5у-6 4) 3(х-7)-(9-2х)=2(12-х)-(х-10) 5) 4(0, 6х-0, 3)-3(0, 7х-0, 1)=0 12. 1) -5у-17у=-50+6 2) 7х+12=10х-3 3) 4х-2(3+х)=9-х 4) 4(2-3х) – 2(9х-8)=15(1-х)+3(4-х) 5) 5(0, 14-0, 23х)+3(0, 3х+0, 1)=0 13. 1) -7х+12х=8-23 2) 33-5х=15-8х 3) 17+3(15-с)=(4-с)=(4-с)-2(с-5) 4) 7(3-х)-3(х-4)=5(3+2х)-2(-3-2х) 5) 0, 6(х-1)-(х+1)=0 14. 1) 16х – 7х= -42 – 39 2) -24+3х=9х+18 3) -3(5а-1)+4а=2а+7(5-3а) 4) 4(х-16) – (8-х)=10(х+1)-2(15+8х) 5) 5(0, 16х+0, 33) – (3-х)=0 15. 1) у-12у=-6-27 2) -15х+31=-7+4х 3) 2(4-9а) – (2а+3)= -8(4-а)+3(1+2а) 4) (х+2)+х=9 5) 1, 24х+3, 46=1, 76х+6, 58 16. 1) -22у-18у=5*(-2) 2) 11-х=55+х 3) 5(2-3в)-4(6+2в)=28-(в-2) 4) 2(х-2)+3=0, 4(х+8) 5) 5, 96-1, 8с=4, 7-2, 7с 17. 1) –х+6х= -45+15 2) 28-4х=19-х 3) -2(3х+4)+(6х+8)=4(5х-2)-(5х+8) 4) 2(5-3х)=6-5х 5) -4, 92у-(0, 08у+5, 12)= - 0, 88-у 18. 1) -27у-33у= - 12*(-5) 2) -35-2х=42+9х 3) 8(4-3у)-(7-2у)= -(6+3у)+8(у-2) 4) 11+2х=55+3х 5) -3(х-2)+4(1+2х)=10, 3+20х 19. 1) х+(7+х)=11 2) (х+8)+(3-2х)=3 3) 10(у-2)=9(у-6) 4) 3(1-х)-5(х+2)=1-4х 5) -15-3х= - 7х+45 20. 1) х+2х-5=40 2) 3х-1-(х+2)=1 3) -5(5-3у)=16(у-3) 4) (2+х)2+(4х-1)3=10х-7 5) -4(1+2х)+3(х-2)= -18, 3 – 20х 21. 1) х+(4+х)+х=16 2) (х-3)+(2х-4)= -1 3) 7(3у-5)= -10(3-2у) 4) (4+5х) – 3(2-х)=16х-0, 4 5) 8(4-3у)-(7-2у)= -(6+3у)+8(у-2) 22. 1) 4х-3+(1-х)= -2 2) 14(3у-2)= -7(4-6у) 3) 2х+0, 1 – 4(1-4х)=8х-4, 4 4) 6х+6=4х-2 5) 2, 44+2, 3р=3, 12+2, 7р 23. 1) 3(х-2)=х+2 2) (х+2)+(4х-3)-(5-х)=1 3) 4х-3=2х+1 4) -2х-4=2х+8 5) 0, 4(х-3)=0, 5(4+х)-2, 5 24. 1) 2(х-3)=7(2+х) 2) 3-(х+1)-(х-4)+(2х-1)=0 3) 2(1-х) – 4(2х+8)=8х+28 4) –(3у+7)=8-2(8-у) 5) 5, 96-1, 8с=4, 7-2, 7с
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