1)cos²a: (sin(a/2)/cos(a/2)-cos(a/2)/sin(a/2)=cos²a: (sin²(a/2)-cos²(a/2)/sin(a/2)cos(a/2)= cos²a: (-2cosa/sina)=-cos²a*sina/2cosa=-(sinacosa)/2=-sin2a/4 2)sin(a+π/4)/cos(a+π/4)-sin(a-π/4)/cos(a-π/4)= (sin(a+π/4)cos(a-π/4)-sin(a-π/4)cos(a+π/4))/cos(a+π/4)cos(a-π/4)= (sin(a+π/4-a+π/4)): 1/2(cos(a+π/4-a+π/4)+cos(a+π/4+a-π/4)= sinπ/2: 1/2(cosπ/2+cos2a)=2/cos2a я решила 2 раза, если бы в примере стоял +,тогда получается 2tg2a.