Вычислить значение первообразной в указанной точке a) f(x)=-3/x^4 и f(2)=1; б)f(x)=cos5x и f(пи/5)=3

f(x)=(1/x^3)+c; f(2)=(1/8)+c=1⇒c=7/8⇒f(x)=(1/x^3)+7/8

f(x)=(1/5)sin5x+c; f(π/5)=c=3 ⇒ f(x)=(1/5)sin5x+3

    sin²x+cos²x+2sin x*cos x=cjs x+sin x     (sin x+cos x)²-(cos x+sin x)=0     sin x+cos x) (sin x+cos x-1)=0      1)sin x+cos x=0   /cos x     tg x=-1   x=-π/4=πn   n∈z       2)sin x+cos x=1     sin x+sin(π/2-x)=1   2sin(x+π/2-x)/2cos (x-π/2+x)/2=1         2sinπ/4*cos(x-π/4)=1     2*√2/2*cos(x-π/4)=1     √2cos(x-π/4)=1     cos (x-π/4)=√2/2     x-π/4= +-π/4+2πn     x=+-π/4+π/4+2πn       x1=π/4+π/4+2πn=π/2+2πn. n∈z   x2=-π/4+π/4+2πk=2πk.   k∈z

  x-2y=-28; x-y=-2  solution :   {x,y} = {24,26}  system of linear equations entered :   [1] x - 2y = -28   [2] x - y = -2 graphic representation of the equations : -2y + x = -28 y + x = -2 olve by substitution : // solve equation [2] for the variable    x      [2] x = y - 2 // plug this in for variable    x    in equation [1]   [1] (y -2) - 2y = -28   [1] - y = -26 // solve equation [1] for the variable    y      [1] y = 26  // by now we know this much :   x = y-2   y = 26 // use the    y    value to solve for    x      x = (26)-2 = 24  solution :   {x,y} = {24,26}