Найти производную) а) (2х-0, 5)^3 б) х^3cos2x в) 2х/1-х

6(2x-1/2)^2

3x^2cos2x-2x^3sin2x

(2(1-x)+2x)/(1-x)^2=2/(1-x)^2

A-sinx=1/2 sinx=-1/2 x=(-1)^(n+1)*π/6+πn,n∈z б 2sinxcosx-cosx=0 cosx(2sinx-1)=0 cosx=0⇒x=π/2+πk,k∈z 5π/6< π/2+πk< 3π 5< 3+6k< 18 2< 6k< 15 1/3< k< 2 1/2 k=1⇒x=π/2+π=3π/2 k=2⇒π/2+2π=5π/2 sinx=1/2⇒x=π/6+2πn u x=5π/6+2πn 5π/6< π/6+2πn< 3π   u   5π/6< 5π/6+2πn< 3π 5< 1+12n< 18   u   5< 5+12n< 18 4< 12n< 17   u   0< 12n< 13 1/3< n1 5/12   u   0< n< 1 1/12 n=1⇒x=π/6+2π=13π/6   u   n=1⇒x=5π/6+2π=17π/6

:20n+3c+n+5c = 21n + 4c.(x² -13x-464)/(x+16) = (x - 29)(x +16)/(x +16) = x - 29(m³+0,9)² = m⁶ + 1,8m² + 0,81 разложите на множители4с⁸-196 = (2c⁴ - 14)(2c⁴ + 14) сократите дробь(15ху-25у²) /5ху = 5y(3x - 5y)/5xy = (3x -5y)/xвычислите    при а=7 +  √  3    b  = 7-  √  3 : (а³  - b³)/(а²  -b²)  : (а²+аb+b²)/(а³+3а²b+3аb²+b³)= =(a - b)(a² +ab +b²)/ (a - b)(a + b) * (a + b)³/(a² +ab +b²)= =(a + b)² (a + b)² = (7 +  √3 + 7 -  √3)² = 14² = 196