в). 3x² + 5x - 2 = 3(x - 1/3)(x + 2) = (3x - 1)(x+ 2);
3x² + 5x - 2 = 0 d = b²-4ac = 25+24 = 49
x₁ = (-b+√d)/2a = (-5+7)/6 = 1/3
x₂ = (-b-√d)/2a = (-5-7)/6 = -2
г). 6x² - 13x + 6 = 6(x - 1,5)(x - 2/3) = (2x - 3)(3x - 2);
6x² - 13x + 6 = 0 d = b²-4ac = 169-144 = 25
x₁ = (-b+√d)/2a = (13+5)/12 = 1,5
x₂ = (-b-√d)/2a = (13-5)/12 = 2/3
Поделитесь своими знаниями, ответьте на вопрос:
Cos a- sin a/sin a* cos a +sin a/ 2cos a
(sin(3п/2+a)+sin(2п+a)/(2cos(-a)sin(-a)+1)=
=-cos a + sin a / (2 cos a * (-sin a) +1) =
=-cos a + sin a / (-2 cos a * sin a + (cos a)^2 +2 cos a * sin a + (sin a)^2 )=
= -cos a + sin a / ((cos a)^2 + (sin a)^2) =
= -cos a + sin a / 1 = sin a - cos a
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