Визначте скільки необхідно теплоти для випаровування 1 кг г води, взятої за температури кипіння

Q = 2257 кДж

Объяснение:

для води L = 2257 кДж/кг

Q = 1 * 2257 кДж = 2257 кДж

1. every day i get up at 6.40. waking up i wash my face, brush my teeth and get dressed. usually for breakfast i eat cookies with tea. i leave at 7.20 or so. i'm going to stop, which is near my house and food on the bus to school.2. my favorite subject in school is history. the lessons of history can learn a lot about how our ancestors lived. i'm sitting on the lessons with anna.3. when the lessons end i just go home. when i get home, the first thing i'm going to eat and rest. and then i sit down to do homework. we ask a lot of homework.4. i watch tv very often, so i have no favorite.5. every sunday i'm meeting with a friend. we go with her to the movies or just walk around the city.6. when i grow up i want to work on the railroad. 7. i go to bed at 23.00. before you go to bed, i listen to music. then i'm going to wash, brush your teeth and go to bed.

T-температура  после того, как установится тепловое равновесиес1-удельная теплоемкость воды =4200 дж/кг*кс2-удельная теплоемкость льда  =2110 дж/кг*кλ- удельная теплота плавления льда=330 кдж/кг*к вода охлаждаетсяq1=c1*m1*(t1-t)=4200*0.200*([273+18]-t) лед нагревается  от т2=  -20 гр. по цельсию  до температуры   0 град с  q2=c2*m2*(0-t2)=2110*0.030*(0-[-20])=1266 джлед плавитсяq3=λm2=330000*0.030=9900 джвода из расплавленного льда нагревается q4=c1*m2*(t-0)=4200*0.030*t