Точки m и n расположены на ребрах треугольной пирамиды. скопируйте рисунок отметьте и обозначьте точки, в которых прямая mnпересекают прямые содержащие другие ребра пирамиды
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Объяснение:
gprs is the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the first of the people who are not in the
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Выражения: а) sin^2 a + sin^2(90°-a)b) tg15°*tg75°-1
3. В треугольнике угол А 60 градусов. ВС-8√3. Найдите радиус описанной окружности.
По свойству биссектрис трапеции они образовывают при боковых сторонах равнобедренные треугольники. Тогда ВК = АВ = 25 см, СК = СД = 30 см, тогда ВС = ВК + СК = 25 + 30 = 55 см.
Построим высоты ВН и СМ. Четырехугольник НВСМ прямоугольник, тогда НМ = ВС = 55 см.
В прямоугольном треугольнике СДМ определим длину катета ДМ.
ДМ2 = СД2 – СМ2 = 900 – 576 = 324.
ДМ = 18 см.
В прямоугольном треугольнике АВН определим длину катета АН.
АН2 = АВ2 – ВН2 = 625 – 576 = 49.
ДМ = 7 см.
Тогда АД = АН + НМ + ДМ = 7 + 55 + 18 = 80 см.
Определим площадь трапеции.
Sавсд = (ВС + АД) * ВН / 2 = (55 + 80) * 24 / 2 = 1620 см2.
ответ: Площадь трапеции равна 1620 см2.