Угол2=45градусов угол7 в 3 раза больше угла2доказать, что a параллельно b?

невозможно.

Объяснение:

если а||в, то <7=<2 как внешние накрестлежащие.

Поскольку равенства нет по условию, то а не параллельно в

Может <8 в 3 раза больше <2 и равен 135° ? Тогда да, <7=180-135=45°==<2, значит а||в

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Основное тригонометрическое тождество:

sin²α + cos²α = 1,      откуда

sinα = √(1 - cos²α)  или  sinα = - √(1 - cos²α)

Знак синуса зависит от координатной четверти, в которой расположен угол.

Но в данной задаче, вероятно, речь идет об остром угле прямоугольного треугольника, поэтому будем рассматривать синус угла только положительный.

tgα = sinα / cosα

1. cosα = 5/13

sinα = √(1 - 25/169) = √(144/169) = 12/13

tgα = 12/13 : 5/13 = 12/5

2. cosα = 15/17

sinα = √(1 - 225/289) = √(64/289) = 8/17

tgα = 8/17 : 15/17 = 8/15

3. cosα = 0,6

sinα = √(1 - 0,36) = √(0,64 ) = 0,8

tgα = 0,8/0,6 = 8/6 = 4/3

Объяснение: